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1>School>Extra>Maths>Qotd solutions>2024-05-14_lnx-differential.html

Question

Solution

Same steps for differential equations.

1ylnydy=dx1ylnydy=dx \begin{align*} \frac{1}{y\ln y}dy&=dx\\ \int\frac{1}{y\ln y}dy&=\int dx\\ \end{align*}

Let u=lnyu=\ln y, and notice dx=x\displaystyle\int dx=x.

1udy=dxlnu=x+Clnlny=x+Cy=keex \begin{align*} \int\frac{1}{u}dy&=\int dx\\ \ln|u|&=x+C\\ \ln|\ln y|&=x+C\\ y&=ke^{e^x} \end{align*}


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